Balancear las siguientes ecuaciones

2 = H = 4
2 = O = 2
2H2 + O2 → 2H2O RESPUESTA
4 = H = 4
2 = O = 2
1 = C = 1
4 = H = 2
2 = O = 2
2CH4 + 3O2 → 2CO + 4H2O RESPUESTA
2 = C = 2
8 = H = 8
6 = O = 6
2 = N = 1
2 = H = 3
N2 + 3H2 → 2NH3 RESPUESTA
2 = N = 2
6 = H = 6
2 = Fe = 1
4 = O = 3
2 = H = 3
Fe2O3 + 3H2O → 2Fe (OH)3 RESPUESTA
2 = Fe = 2
6 = O = 6
6 = H = 6