AYUDENME ES DEL TEMA DE SECTOR CIRCULAR

Respuesta:
[tex]\frac{25}{64}[/tex]
Explicación paso a paso:
[tex]x + \frac{1}{8}[/tex] [tex]= (x^{2}) x[/tex]
[tex]\frac{8x + 1}{8} = x^{3} + x \\8x + 1 = 8x^{3} + 8x\\\frac{1}{8} = x^{3} \\\frac{1}{2} = x[/tex]
[tex]L = \frac{1}{8} + \frac{1}{2} = \frac{5}{8} \\x = \frac{1}{2} \\r = (\frac{1}{2})^{2} + 1 =\frac{5}{4}[/tex]
[tex]A = \frac{(\frac{5}{8})^{2} }{2(\frac{1}{2})} = \frac{25}{64\\}[/tex]