Respuesta :
Respuesta:
F(x) = sen^2(x)+c
F ' (x) = d/dx[sen ^2(x)+c ]
F ' (x) = d/dx[sen^2(x)] + d/dx [ c ]
F ' (x) = d/dx[2sen(x)]×d/dx[sen(x)]+0
F ' (x) = 2sen(x)×cos(x)
F ' ( x) = sen(2x)
Explicación paso a paso:
Respuesta:
F(x) = sen^2(x)+c
F ' (x) = d/dx[sen ^2(x)+c ]
F ' (x) = d/dx[sen^2(x)] + d/dx [ c ]
F ' (x) = d/dx[2sen(x)]×d/dx[sen(x)]+0
F ' (x) = 2sen(x)×cos(x)
F ' ( x) = sen(2x)
Explicación paso a paso: