Respuesta:
ver solución ._.
Explicación paso a paso:
a. [tex]a^{2}.a^{2}.a = a^{3+2+1} = a^{6} \\[/tex]
b. [tex](b^{6}.b^{5}):b^{7} = b^{6+5-7} = b^{4}[/tex]
c. [tex](m^{4}.m)^{2} = m^{8} .m^{2} = m^{10}[/tex]
d. [tex](s^{3} .s.s^{5})^{3} = s^{9}.s^{3}.s^{15} = s^{27}[/tex] :-)
