Respuesta :
Respuesta:
[tex]a {x}^{2} + bx = 0 \\ (a {x}^{2} + bx) \div a = {x}^{2} + \frac{bx}{a} [/tex]
[tex] {()}^{2} - {u}^{2} = c \\ c = 0[/tex]
[tex] {( \frac{ - b}{2a} )}^{2} - {u}^{2} = 0[/tex]
[tex] \frac{ - b}{2a} - u \: \: \: \: \frac{ - b}{2a} + u[/tex]
........... Kd