Taller:
[tex]\left(\frac{3}{5}x^2-\frac{4}{5}x+\frac{2}{5}\right)+\left(x-\frac{2}{5}x^2+\frac{7}{5}\right)[/tex]
Solucion:
[tex]=\frac{3}{5}x^2-\frac{4}{5}x+\frac{2}{5}+x-\frac{2}{5}x^2+\frac{7}{5}[/tex]
[tex]=\frac{3}{5}x^2-\frac{2}{5}x^2-\frac{4}{5}x+x+\frac{2}{5}+\frac{7}{5}[/tex]
[tex]=\frac{3}{5}x^2-\frac{2}{5}x^2=\frac{1}{5}x^2[/tex]
[tex]=\frac{1}{5}x^2-\frac{4}{5}x+x+\frac{2}{5}+\frac{7}{5}[/tex]
[tex]-\frac{4}{5}x+x=\frac{1}{5}x^2[/tex]
[tex]=\frac{1}{5}x^2+\frac{1}{5}x+\frac{2}{5}+\frac{7}{5}[/tex]
[tex]=\frac{1}{5}x^2==\frac{x}{5}^2[/tex]
[tex]\frac{x}{5}x=\frac{x}{5}[/tex]
[tex]=\frac{x^2}{5}+\frac{x}{5}+\frac{2}{5}+\frac{7}{5}[/tex]
[tex]=\frac{x^2+x+2+7}{5}[/tex]
[tex]=\frac{x^2+x+9}{5}[/tex]
[tex]Psicopatacolombiano2[/tex]
