Dados los conjuntos:U = {1, 2, 3, 4, 5, 6, 7, 8}A = {x-1 / x  N, 2  x  6}B = {x/x  N, 2  x  5}C = {x  N / (x - 1) (x - 2) (x-6)= 0}Hallar: [(B  C)’ – (A  B C)]